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A boat is moving due east in a region where the earth's magnetic field is 5.0 × 10^5N/Am due north and horizontal. The boat carries a vertical aerial 3m long. if the speed of the boat is 2.50 m/s, what is the magnitude of the induced emf in the wire of aerial?
A. 3.75 × 10^-4 V
B. 3.75 × 10^-4 mV
C. 375 × 10^-4 V
D. 1 mV
E. none of the above​

Respuesta :

skyluke89

The induced emf is A) [tex]3.75\cdot 10^{-4} V[/tex]

Explanation:

For a conductive wire moving in a region of magnetic field, the induced electromotive force (induced emf) can be found with the equation

[tex]\epsilon = BvL[/tex]

where

B is the strength of the magnetic field

v is the speed of the wire

L the length of the wire

In this problem, we have:

L = 3 m

v = 2.50 m/s

[tex]B=5.0\cdot 10^{-5} N/Am[/tex]

Substituting, we find the induced emf:

[tex]\epsilon = (5.0\cdot 10^{-5})(2.50)(3)=3.75\cdot 10^{-4} V[/tex]

Learn more about magnetic fields:

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