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What is the surface area of the rectangular pyramid below?

A rectangular pyramid. The rectangular base has a length of 4.8 meters and height of 3.8 meters. 2 triangular sides have a base of 4.8 meters and height of 2.6 meters. 2 triangular sides have a base of 3.8 meters and height of 2.9 meters.

Respuesta :

calculista

Answer:

[tex]SA=41.74\ m^2[/tex]

Step-by-step explanation:

we know that

The surface area of the rectangular pyramid is equal to the area of its rectangular base plus the area of its four triangular faces

so

step 1

Find the area of its rectangular base

[tex]A=(4.8)(3.8)[/tex]

[tex]A=18.24\ m^2[/tex]

step 2

Find the area of its four triangular faces

[tex]A=2[\frac{1}{2}(4.8)(2.6)]+2[\frac{1}{2}(3.8)(2.9)][/tex]

[tex]A=12.48+11.02=23.5\ m^2[/tex]

step 3

Find the surface area

Adds the areas

[tex]SA=18.24+23.5[/tex]

[tex]SA=41.74\ m^2[/tex]

Answer:

Step-by-step explanation:The area of the base is 24 cm2.

There are four lateral faces.

The total surface area of the figure is 66.4 cm2.

i just did the test

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