1) The energy used in 30 days is [tex]E=4.88\cdot 10^9 J[/tex]
2) The energy used per day is [tex]1.63\cdot 10^8 J[/tex]
Explanation:
1)
We start by calculating the energy used for 30 days. We are told that the energy used in 30 days is
[tex]E=1355 kWh[/tex]
We have to convert this energy from kWh to Joules. First of all, we keep in mind that
1 kW = 1000 W
So the actual energy used is
[tex]E=1355 \cdot 1000 = 1.355\cdot 10^6 Wh[/tex]
This energy is expressed as product between power (P) and time (t):
[tex]E=P\cdot t = (1.355\cdot 10^6 W)\cdot (1h)[/tex]
And since 1 hour = 3600 s,
[tex]E=(1.355\cdot 10^6 W)\cdot (3600 s)[/tex]
And by multiplying, we find:
[tex]E=4.88\cdot 10^9 J[/tex]
2)
In order to find the energy used in Joules per day, we have to divide the total energy by the number of days, 30.
The total energy used in 30 days is (calculate in part 1):
[tex]E=4.88\cdot 10^9 J[/tex]
Now, we just need to divide by the number of days, N = 30:
[tex]\frac{E}{N}[/tex]
Therefore, we find:
[tex]E_1 = \frac{4.88\cdot 10^9}{30}=1.63\cdot 10^8 J[/tex]
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