Answer:
First option and Fourth option.
Step-by-step explanation:
To solve this exercise you need to use the following Trigonometric Identity:
[tex]sin\alpha=\frac{opposite}{hypotenuse}[/tex]
In this case you know that:
[tex]\alpha =C[/tex]
Since triangle ABC is similar to triangle DEF:
[tex]\angle C=\angle F[/tex]
Let's begin with the triangle ABC.
You can identify that:
[tex]opposite=AB\\hypotenuse=AC[/tex]
Then, substituing values, you get:
[tex]sinC=\frac{AB}{AC}[/tex]
In triangle DEF, you know that:
[tex]opposite=DE\\hypotenuse=DF[/tex]
So, substituing values, you get:
[tex]sinF=sinC=\frac{DE}{DF}[/tex]