Answer:
There are [tex]4[/tex] unique ways in which three-topping meat pizza can be made.
Step-by-step explanation:
Let number of items that pizza restaurant has [tex](n)[/tex] is [tex]4[/tex]. That are hamburger, pepperoni, Canadian bacon, and sausage.
Also, it asks for three-topping meat pizza. It means [tex](k)=[/tex] [tex]3[/tex]
Plugging these value in the formula we get,
[tex]_nC_k=\frac{n\ !}{k\ !(n-k)\ !}\\\\_4C_3=\frac{4\ !}{3\ !(4-3)\ !}\\ \\_4C_3=\frac{4\times3\times2\times1}{3\times2\times1(1\ !)}\\\\_4C_3=\frac{24}{6\times1} \\\\_4C_3=4[/tex]
So, there are [tex]4[/tex] unique ways in which three-topping meat pizza can be made.
