Answer: [tex]-13.33 m/s^{2}[/tex]
Step-by-step explanation:
We can solve this problem with the following equation:
[tex]a=\frac{V-V_{o}}{\Delta t}[/tex]
Where:
[tex]a[/tex] is the acceleration of the car
[tex]V_{o}=28 m/s[/tex] is the initial velocity of the car
[tex]V=0 m/s[/tex] is the final velocity of the car
[tex]\Delta t=2.1 s[/tex] Is the time in which the car came to a stop
Solving:
[tex]a=\frac{0 m/s - 28 m/s}{2.1 s}[/tex]
[tex]a=-13.33 m/s^{2}[/tex] This is the car's acceleration, note the negative sign indicates the car was decreasing its velocity before coming to a stop.
