Respuesta :

[tex]\bf y = \cfrac{\stackrel{\textit{degree of 1}}{x^1}}{\underset{\textit{degree of 2}}{x^2-16}}[/tex]   when the degree of the denominator is greater than that of the numerator, the only horizontal asymptote occurs at y = 0.

The horizontal asymptote for the given function is y=-16.

The given function is y=x/x²-16.

We need to find the horizontal asymptote for the given function.

What is the horizontal asymptote?

A horizontal asymptote is a horizontal line that is not part of a graph of a function but guides it for x-values. “far” to the right and/or “far” to the left.

Find the horizontal asymptotes by comparing the degrees of the numerator and denominator.

Vertical Asymptotes:

x=0

Horizontal Asymptotes:

y=-16

No Oblique Asymptotes

Therefore, the horizontal asymptote for the given function is y=-16.

To learn more about the asymptotes visit:

https://brainly.com/question/17767511.

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