Answer:
[tex]3\frac{3}{16}[/tex] meter
Step-by-step explanation:
We have to write first what is known from the information.
Let's say, length is L, width is W, and height is H
1. The length of the box is 2 1/2 m = 2,5 m = 5/2 m, it is 1 9/16 = 25/16 times it's width (L). So we have the equation :
L ≡ [tex]\frac{5}{2} = \frac{25}{16} W[/tex]
Then we find the W. From the fraction above, we found W equals to [tex]\frac{8}{5} = 1,6[/tex] meter
2. What is the height of the box, if its volume is 12 3/4 m^3 = 51/4 m^3
Formula of a volume is :
The area wide times the height
In this problem, the equation is :
L × W × H = Volume
Insert the numbers,
[tex]\frac{5}{2}[/tex] × [tex]\frac{8}{5}[/tex] × H = [tex]\frac{51}{4}[/tex]
From the fraction above, we can find that H equals to
[tex]3\frac{3}{16}[/tex] meter
