Answer:
x = 14, y = 3 → (14, 3)
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}x+8y=28&\text{multiply both sides by 3}\\-3x+5y=3\end{array}\right\\\underline{+\left\{\begin{array}{ccc}3x+24y=84\\-3x+5y=3\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad29y=87\qquad\text{divide both sides by 29}\\\\.\qquad\qquad\dfrac{29x}{29}=\dfrac{87}{29}\\\\.\qquad\qquad \boxed{y=3}\\\\\text{Put the value of}\ y\ \text{to the first equation:}\\\\x+8(3)=38\\x+24=38\qquad\text{subtract 24 from both sides}\\x+24-24=38-24\\\boxed{x=14}[/tex]
