Answer:
D. Na₃X
Explanation:
We have the neutral compound Ba₃(X)₂. The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule.
3 × qBa + 2 × qX = 0
3 × (+2) + 2 × qX = 0
2 × qX = -6
qX = -3
If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.
The formula that would be most adequate for the compound framed with sodium and polyatomic would be:
D). Na₃X
Given that,
Neutral Compound = Ba₃(X)₂
The charge in totality(0) = sum of ions' charge × the number of molecular ions
⇒ [tex]3[/tex] × [tex]qBa[/tex] + [tex]2[/tex] × [tex]qX[/tex] [tex]= 0[/tex]
⇒ [tex]3[/tex] × [tex](+2)[/tex] + [tex]2[/tex] × [tex]qX = 0[/tex]
⇒ [tex]2[/tex] × [tex]qX = -6[/tex]
⇒ [tex]qX = -3[/tex]
In case the cation [tex]Na^{+}[/tex], as well as, [tex]X^{3-}[/tex], are present, the molecule that is neutral would need [tex]3Na^{+}[/tex]along with [tex]1 X^{3-}[/tex]
Thus, the produced compound would be [tex]Na_{3}X[/tex]
Thus, option D is the correct answer.
Learn more about 'Sodium' here:
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