Answer:
[tex]CH_{4}[/tex]
Explanation:
We know from laws of diffusion that [tex]rate\alpha\sqrt{\frac{T}{m} }[/tex].
In the given question , it is said that temperature is same in both the cases .
So for rate to become half , molecular mass must be 4 times,ie,
Mass of required gas = 4×mass of He=4×4=16.
Therefore the gas is [tex]CH_{4}[/tex]