The current in the set of lights is 0.6 A
Explanation:
First of all, we need to calculate the equivalent resistance of the string of lights. Assuming they are all connected in series, the total resistance of the lights is given by
[tex]R=R_1 + R_2 + ... R_n[/tex]
Since we have 25 lights all with the same resistance of
[tex]R_i = 8.0 \Omega[/tex]
This means that the total resistance of the set of lights is
[tex]R=25 R_i = 25(8.0)=200 \Omega[/tex]
Now we can find the current passsing through them by using Ohm's law:
[tex]V=IR[/tex]
where
V is the potential difference
I is the current
R is the total resistance
In this problem we have:
V = 120 V
[tex]R=200 \Omega[/tex]
Solving for I, we find the current:
[tex]I=\frac{V}{R}=\frac{120}{200}=0.6 A[/tex]
Learn more about Ohm's law:
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