Answer:
The silver ion concentration is 2.54 * 10^-4 M
Explanation:
Step 1: Data given
Ksp of Ag2CO3 = 8.1 * 10^-12
Step 2: The balanced equation
Ag2CO3 ⇌ 2Ag+ + CO3^2-
Step 3: The initial concentration
Ag2CO3: X M
Ag+: 0M
CO3^2- : 0M
Step 4: The concentration at equilibrium
Ag2CO3: There will react X
Ag+: There will react 2X ⇒ we will have (2X) M
CO3^2-: there will react X ⇒ we will have X M
Step 5:
Ksp = 8.1 * 10^-12 = [Ag+]² * [CO3^2-]
Ksp = 8.1 * 10^-12 = (2x)² * X = 4X³
X = 1.27 * 10^-4
[Ag+] = 2X = 2 *1.27 * 10^-4 = 2.54 * 10^-4 M
The silver ion concentration is 2.54 * 10^-4 M
