Sarah bought 4 first class tickets and 2 coach tickets.
Step-by-step explanation:
Given,
Cost of coach ticket = $310
Cost of first class tickets = $1220
Number of people = 6
Total amount used = $5500
Let,
x represent the number of coach tickets.
y represent the number of first class tickets.
According to given situation;
x+y=6 Eqn 1
310x+1220y=5500 Eqn 2
Multiplying Eqn 1 by 310
[tex]310(x+y=6)\\310x+310y=1860\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](310x+1220y)-(310x+310y)=5500-1860\\310x+1220y-310x-310y=3640\\910y=3640[/tex]
Dividing both sides by 910
[tex]\frac{910y}{910}=\frac{3640}{910}\\y=4[/tex]
Putting y=4 in Eqn 1
[tex]x+4=6\\x=6-4\\x=2[/tex]
Sarah bought 4 first class tickets and 2 coach tickets.
Keywords: linear equation, elimination method
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