To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $4 per hour. The chemistry club wants to spend less than $43 on renting the room. What are the possible numbers of hours the chemistry club could rent the meeting room?

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nExOn

To rent a certain meeting room, a college charges a reservation fee of $31 and an additional fee of $5.90 per hour.

The chemistry club wants to spend less than $84.10 on renting the meeting room.

What are the possible amounts of time for which they could rent the meeting room?

Use t for the number of hours the meeting room is rented, and solve your inequality for t.

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Your inequality is

31 + 5.9*t < 84.10.

To solve it, collect the constant terms on the right side:

5.9*t < 84.10 - 31 = 53.10,

Hence, t < 53.10%2F5.9 = 9 hours.

Answer:

9 Hours

Step-by-step explanation

Divide 43 by 4 to get an estimate of ten

You get 40 so add it with 15

Doesnt Work.

So make it 9 instead of 10 cuz 10 is more than 43.