Sulfuryl dichloride is formed when sulfur dioxide reacts with chlorine.

The data refer to 298 K.

SO2(g) + Cl2(g) -->SO2Cl2(g)

Substance: SO2(g) + Cl2(g) -> SO2Cl2(g)

Delta H� f (kJ/mol): �296.8 0�364.0

Delta G� f (kJ/mol): �300.1 0 �320.0

Delta S�(J/Kmol): 248.2 223.0 311.9

What is the value of G� for this reaction at 600 K?

Respuesta :

Answer: The value of [tex]\Delta G^o[/tex] of the reaction is 28.38 kJ/mol

Explanation:

For the given chemical reaction:

[tex]SO_2(g)+Cl_2(g)\rightarrow SO_2Cl_2(g)[/tex]

  • The equation used to calculate enthalpy change is of a reaction is:

[tex]\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}][/tex]

The equation for the enthalpy change of the above reaction is:

[tex]\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(SO_2Cl_2(g))})]-[(1\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(Cl_2(g))})][/tex]

We are given:

[tex]\Delta H^o_f_{(SO_2Cl_2(g))}=-364kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H^o_f_{(Cl_2(g))}=0kJ/mol[/tex]

Putting values in above equation, we get:

[tex]\Delta H^o_{rxn}=[(1\times (-364))]-[(1\times (-296.8))+(1\times 0)]=-67.2kJ/mol=-67200J/mol[/tex]

  • The equation used to calculate entropy change is of a reaction is:

[tex]\Delta S^o_{rxn}=\sum [n\times \Delta S^o_f_{(product)}]-\sum [n\times \Delta S^o_f_{(reactant)}][/tex]

The equation for the entropy change of the above reaction is:

[tex]\Delta S^o_{rxn}=[(1\times \Delta S^o_{(SO_2Cl_2(g))})]-[(1\times \Delta S^o_{(SO_2(g))})+(1\times \Delta S^o_{(Cl_2(g))})][/tex]

We are given:

[tex]\Delta S^o_{(SO_2Cl_2(g))}=311.9J/Kmol\\\Delta S^o_{(SO_2(g))}=248.2J/Kmol\\\Delta S^o_{(Cl_2(g))}=223.0J/Kmol[/tex]

Putting values in above equation, we get:

[tex]\Delta S^o_{rxn}=[(1\times 311.9)]-[(1\times 248.2)+(1\times 223.0)]=-159.3J/Kmol[/tex]

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

[tex]\Delta G^o_{rxn}=\Delta H^o_{rxn}-T\Delta S^o_{rxn}[/tex]

where,

[tex]\Delta H^o_{rxn}[/tex] = standard enthalpy change of the reaction =-67200 J/mol

[tex]\Delta S^o_{rxn}[/tex] = standard entropy change of the reaction =-159.3 J/Kmol

Temperature of the reaction = 600 K

Putting values in above equation, we get:

[tex]\Delta G^o_{rxn}=-67200-(600\times (-159.3))\\\\\Delta G^o_{rxn}=28380J/mol=28.38kJ/mol[/tex]

Hence, the value of [tex]\Delta G^o[/tex] of the reaction is 28.38 kJ/mol