Answer:
2.243%
Explanation:
Molecular weight calculation:
55.845 + (15.9994 + 1.00794)*2
Molar mass of Fe(OH)2 = 89.85968 g/mol
Mass percent= molar mass of Hydrogen/molar mass of fe(OH)2 x 2 mol H/1mol Fe(OH)2 x 100%
= 1.00794/89.85968 x 100%
= 2.243%
Answer:
2.25 % (≈2%) of Fe(OH)2 are hydrogen atoms
Explanation:
Step 1: Data given
Molar mass of Fe(OH)2 = 89.86 g/mol
Molar mass of H = 1.01 g/mol
Step 2: Calculate mass % of hydrogen
For 1 molecule Fe(OH)2 we have 2 hydrogen atoms
Molar mass for 1 hydrogen is 1.01 g/mol, but since we have 2 hydrogen atoms per 1 molecule Fe(OH)2 is this 2*1.01 = 2.02 g/mol
% = mass of hydrogen atoms / mass of the Fe(OH)2 molecule
% = (2.02 grams / 89.86 grams)*100%
% = 2.25 % ≈2
2.25 % (≈2%) of Fe(OH)2 are hydrogen atoms
