Answer:
Step-by-step explanation:
X- no of students who accept is B(1200,0.83)
a) Mean of X = [tex]np=1200*0.83\\= 996[/tex]
Std deviation of X = [tex]\sqrt{npq} =\sqrt{996(0.17)} \\=13.0123[/tex]
b) For normal approximation we have
X is N(996, 13.0123)
[tex]P(X\geq 790)\\= P(X>789.5)\\=1[/tex]
(almost 1)
(continuity correction applied)\
c) P(X>1000) = P(X>1000.5) (after continuity correction)
=0.3647
d) Now X is Binomial with (1150, 0.83)
Apprx X is N( 954.5,12.7383)
P(X>1000)
= P(X>1000.5)
= 0.0002