Answer:
[tex]A'B'=9\ in[/tex]
Step-by-step explanation:
The correct question is
Under a dilation, triangle A(0,0), B(0,3). C(5,0) becomes triangle A'B'C'. The scale factor for this dilation is 3
what is the length of A'B' inches
see the attached figure
we know that
The length of segment A'B' is equal to the length of segment AB multiplied by 3
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have
A(0,0), B(0,3)
substitute
[tex]AB=\sqrt{(3-0)^{2}+(0-0)^{2}}[/tex]
[tex]AB=\sqrt{(3)^{2}+(0)^{2}}[/tex]
[tex]AB=3\ in[/tex]
therefore
[tex]A'B'=3(AB)[/tex]
[tex]A'B'=3(3)=9\ in[/tex]
