Answer: 20580 Joules of work is done by the firefighter.
Explanation:
Work done is defined as the force times distance travelled.
work=[tex]mass\times acceleration\times height[/tex]
Given:
mass= 75 kg
acceleration due to gravity = [tex]9.80m/s^2[/tex]
h= height = 28 m
Putting in the values we get,
work=[tex]75kg\times 9.80m/s^2\times 28m=20580kgm^2s^{-2}=20580J[/tex]
[tex]1kgm^2s^{-2}=1Joule(J)[/tex]
Thus 20580 Joules of work is done by the firefighter.
The amount of work done by the firefighter is equal to 20,580 Joules.
Given the following data:
Scientific data:
To determine how much work is being done by the firefighter:
The work done by a body is simply the product of the perpendicular force acting on the body and the distance it covers.
Mathematically, work done is given by the formula:
[tex]Work\;done = Force \times distance[/tex] ......equation 1.
But, [tex]Force = mg[/tex] ......equation 2.
Substituting eqn. 2 into eqn. 1, we have:
[tex]Work\;done = mgh\\\\Work\;done =75 \times 9.8 \times 28[/tex]
Work done = 20,580 Joules
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