Respuesta :
Answer:
D. [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
We have been given that a bag contains x blue chips and y red chips. The probability of selecting a red chip at random is 3/7. We are asked to find the [tex]\frac{x}{y}[/tex].
[tex]\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}[/tex]
[tex]P(\text{Red})=\frac{\text{Number of red chips}}{\text{Total number of chips}}[/tex]
[tex]P(\text{Red})=\frac{y}{x+y}[/tex]
Since we are told that probability of selecting a red chip at random is 3/7, so red balls are 3 and total balls are 7:
[tex]P(\text{Red})=\frac{3}{x+3}[/tex]
Since total balls are 7, so we will get:
[tex]x+3=7\\x=4[/tex]
Upon substituting [tex]x=4\text{ and } y=3[/tex] in expression [tex]\frac{x}{y}[/tex], we will get:
[tex]\frac{4}{3}[/tex]
Therefore, the value of [tex]\frac{x}{y}[/tex] is [tex]\frac{4}{3}[/tex] and option D is the correct choice.
