Answer:
The magnitude of the maximum possible force is 3.57 newtons.
Explanation:
The magnetic force on a wire is:
[tex]\overrightarrow{F}=I(\overrightarrow{L}\times\overrightarrow{B}) [/tex]
with I the current, L the length of the wire and B the magnitude magnetic field. So, the magnitude of the force is:
[tex]F=ILB\sin\theta [/tex] (1)
with [tex]\theta [/tex] the angle between the wire and the magnetic field, the maximum possible value is when the wire and magnetic field are perpendicular to each other [tex]\theta= 90Celsius\,degree [/tex] then [tex]\sin(90)=1 [/tex] so by (1):
[tex]F_{max}=ILB=(20.4A)(0.92m)(0.19T)[/tex]
[tex]F_{max}=3.57N [/tex]
