Answer:
Mass of the frog M = 706.85 Kg
Explanation:
Given Data:
The density of fluid is: ρo=1.30g/cm3
The radius of pod is: R=5cm
The expression for volume of pod is
Vo=4/3πR^3
The frog in a hemisphere pod just float without sinking so the buoyancy force applied on pod by fluid that is weight of fluid displaced.
The expression for buoyancy fore that is weigh of fluid displaced is
f=ρoVog
The expression for weight of floating object is
Wg=Mg
Here M is mass of frog
The buoyancy force equal to weight of the floating object
f=Wg ρo Vo g=MgM=ρoVo
Substitute the value and solve the above expression
M=ρoVo=ρo4/3πR^3
[tex]M= 1.35\times\frac{4}{3}\pi5^3[/tex]
M= 706.85834 Kg
From the information provided in the question, the mass of the frog is 354 g.
From the question, we have the following information;
Density of the fluid = 1.35 g/cm3
radius of the pod = 5.00 cm
Let us recall that the volume of a hemisphere is given by;
V = 2/3 πr^3
Volume of the pod = 2/3 × 22/7 × (5.00)^3
Volume of the pod = 262 cm^3
Recall that the pod has a negligible mass hence the mass is that of the frog.
Since;
Density= mass/volume
mass = Density × volume
Mass = 1.35 g/cm3 × 262 cm^3
Mass = 354 g
Hence, the mass of the frog is 354 g
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