Answer:
[tex]4-ethyl-hept-2,5-diene[/tex]
Explanation:
Hello,
In this case, by following the IUPAC rules, we first must number the chain starting by the first left-handed CH₃ and finishing at the last CH₃. In such a way, the radical C₂H₅ which is at the fourth carbon is an ethyl radical as it has two carbons. Moreover, we notice the presence of two double bonds at the second and fifth carbons and a main chain having seven carbons in total, for that reason, the name turns out:
[tex]4-ethyl-hept-2,5-diene[/tex]
Best regards.
