A jar contains n nickels and d dimes. There is a total of 253 coins in the jar. The value of the coins is $15.95. How many nickels and how many dimes are in the jar?

Respuesta :

There are 187 nickels and 66 dimes in the jar.

Step-by-step explanation:

Given,

Total coins = 253

Value of coins = $15.95 = 15.95*100 = 1595 cents

Value of each nickel = 5 cents

Value of each dime = 10 cents

According to given statement;

x+y=253     Eqn 1

5x+10y=1595     Eqn 2

Multiplying Eqn 1 by 5

[tex]5(x+y=253)\\5x+5y=1265\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](5x+10y)-(5x+5y)=1595-1265\\5x+10y-5x-5y=330\\5y=330[/tex]

Dividing both sides by 5

[tex]\frac{5y}{5}=\frac{330}{5}\\y=66[/tex]

Putting y=66 in Eqn 1

[tex]x+66=253\\x=253-66\\x=187[/tex]

There are 187 nickels and 66 dimes in the jar.

Keywords: linear equation, elimination method

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