Respuesta :
Answer:
[tex]\frac {7}{36}[/tex] .
Step-by-step explanation:
Let,
A = The event that a player selected at random from the Eastern Division team is not a Canadian - born player.
B = The event that a player selected at random from the Western Division team is not a Canadian - born player.
We are to find out, P(A∩B).
According to the question,
P(A∩B)
= [tex]P(A) \times P(B)[/tex] [Since, A, B are independent]
= [tex]\frac {14}{8 + 14 + 2} \times \frac {8}{12 + 8 + 4}[/tex]
= [tex]\frac {14}{24} \times \frac {8}{24}[/tex]
= [tex]\frac {7}{12} \times \frac {1}{3}[/tex]
= [tex]\frac {7}{36}[/tex]
