Answer:
1.2 ft/s or 72 ft/min
Explanation:
To solve this problem, we can use the relationship between the angular and linear speed for this particular movement (rotation). As the speed of the current is tangent to the trajectory of the wheel we can define as follows:
[tex]v= \omega r=18 \frac{rev}{min} \times \frac{1min}{60s}\times 4 ft\\v= 1.2 \frac{ft}{s}= 72 \frac{ft}{min}[/tex]
The speed of the current is 72 ft/min
