A beaker has 0.2 M of Na2SO4. What will be the concentration of sodium and sulfate ions?
[Na+] = 0.4 M, [SO42-] = 0.2 M
[Na+] = 0.2 M, [SO42-] = 0.2 M
[Na+] = 0.4 M, [SO42-] = 0.4 M
[Na+] = 0.2 M, [SO42-] = 0.4 M

Respuesta :

The concentration of sodium and sulphate ions are [[tex]Na^+[/tex]] = 0.4 M, [[tex]SO_4^2-[/tex]] = 0.2 M

Explanation:

The molar concentration is defined as the number of moles of a molecule or an ion in 1 liter of a solution.

In the given solution, the concentration of the salt sodium sulphate is 0.2M. So, 0.2 moles of sodium sulphate is present in 1 liter of solution.

Assuming 100% dissociation,

1 molecule of sodium sulphate gives 2 ions of sodium and 1 ion of sulphate.

So 0.2 moles of sodium sulphate will give 0.4 moles of sodium ions and 0.2 moles of sulphate ions.