Answer:
Speed = 0.296m/2
Period = 0.203 s
Explanation:
If by 'long' you mean the wavelength of the waves, then the wavelength [tex]\lambda=0.06m[/tex].
The frequency [tex]f[/tex] of the waves is 14.8 waves every 3 seconds or
[tex]f=14.8/3 =4.33Hz[/tex].
Now the relationship between wavelength [tex]\lambda[/tex], frequency [tex]f[/tex] and speed [tex]v[/tex] of the waves is:
[tex]v=\lambda f[/tex]
We put in the values [tex]\lambda=0.06m[/tex] and [tex]f=4.933Hz[/tex] and get:
[tex]\boxed{v=0.06*4.922=0.296m/s}[/tex]
Now the period [tex]T[/tex] is just the inverse of the frequency, or
[tex]T=\frac{1}{f}[/tex]
[tex]\boxed{T=\frac{1}{4.933}=0.203\:seconds }[/tex]
