Answer:
The current at t= 0 sec, is 0 A
The current at t= 0.5 sec, is 2.2 A
The current at t= 1 sec, is 4.4 A
Explanation:
Given that
q(t) = 2.2 t²
We know that:- the change in the charge w.r.t. time is known as current. So,
[tex]I=\dfrac{dq}{dt}[/tex]
q(t) = 2.2 t²
[tex]\dfrac{dq}{dt}= 4.4 t[/tex]
I= 4.4 t
1.
t = 0 s :
I = 4.4 x 0 = 0 A
Therefore, the current at t= 0 sec, is 0 A
2 .
t= 0.5 s :
I = 4.4 x 0.5 = 2.2 A
Therefore, the current at t= 0.5 sec, is 2.2 A
3.
t= 1 s
I = 4.4 x 1 =4.4 A
Therefore, the current at t= 1 sec, is 4.4 A
