What is the limit of the infinite series?



∑ ( 3n^5/4n^5+1)

n=1



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What is the limit of the infinite series 3n54n51n1 Enter your answer in the box Enter any fraction as a simplified fraction class=

Respuesta :

Answer:

does not exist

Step-by-step explanation:

According to the divergence test, for an infinite series ∑ aₙ, the series diverges if lim(n→∞) aₙ ≠ 0.

Applying the divergence test here:

lim(n→∞) (3n⁵ / (4n⁵ + 1)) = 3/4

This is not 0, so the series does not converge, meaning the sum does not exist.

The limit of the infinite series is [tex]\frac{3}{4}[/tex]

Definition of limit :

  • A function f(x) limit exist at x = a if,

      [tex]\lim_{x \to a+} f(x)= \lim_{x \to a-} f(x)=f(a)[/tex]

  • The limit of a series is the value the series when n approaching n → ∞ .
  • Given function is,

                   [tex]\sum_{n=1}^{\infty} \frac{3n^{5} }{4n^{5}+1 }[/tex]

The value of  limit of a series is ,

          [tex]\lim_{n \to \infty} \frac{3n^{5} }{4n^{5}+1 }=\frac{3n^{5} }{n^{5}(4+\frac{1}{n^{5} } ) }\\\\ \lim_{n \to \infty} \frac{3 }{(4+\frac{1}{n^{5} } ) }=\frac{3}{4}[/tex]

The limit of the infinite series is [tex]\frac{3}{4}[/tex]

Learn more about the limit of the function here:

https://brainly.com/question/1444047