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A runner is training for an upcoming marathon by running around a 80-m-diameter circular track at constant speed. Let a coordinate system have its origin at the center of the circle with the x-axis pointing east and the y-axis north. The runner starts at (x, y) = (48 m, 0 m) and runs 2.5 times around the track in a clockwise direction.1. What is the magnitude of his displacement vector?2. What is the direction of his displacement vector?

Respuesta :

Answer:

Explanation:

Given

diameter [tex]d=80\ m[/tex]

runner start at (x,y)=(48 m,0 m)

Runner runs around the circle 2.5 times

i.e. he runs two and half rounds

displacement of two rounds is zero so net displacement is of half round

displacement [tex]=\pi \cdot 48=150.816\ m[/tex]

After 2.5 round he will be towards west direction with respect to origin

so direction of displacement vector is west

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