Answer: The required probability is 0.1328.
Step-by-step explanation:
Since we have given that
n = 5
Probability of success = p = defective rate = 3% = 0.03
Probability of failure = q = 1-p = 1 - 0.03 = 0.97
So, we will use "Binomial distribution":
probability that the first defective occurs in the fifth item inspected would be
[tex]P(X=1)=^5C_1(0.03)^1(0.097)^4\\\\P(X=1)=0.1328[/tex]
Hence, the required probability is 0.1328.
