Answer:
Explanation:
Given
mass of ball [tex]m=0.5\ kg[/tex]
when it is struck by a mallet then average force exerted is [tex]F_{avg}=270\ N[/tex]
suppose v is the velocity of ball after collision then
change in momentum of ball is given by
[tex]\Delta P=m(v-0)=0.5\cdot v[/tex]
and impulse given by change in momentum of object when an force is applied for a period of time
if t is the time of contact
[tex]F_{avg}\times t=\Delta P[/tex]
[tex]t=\frac{\Delta P}{F_{avg}}[/tex]
[tex]t=\frac{270}{0.5\cdot v}[/tex]
[tex]t=\frac{540}{v}[/tex]
Now velocity after impact v=3\ m/s
[tex]t=\frac{540}{3}[/tex]
[tex]t=180\ s[/tex]
