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The driver of a car traveling at 26.1 m/s applies the brakes and undergoes a constant deceleration of 1.64 m/s 2 . How many revolutions does each tire make before the car comes to a stop, assuming that the car does not skid and that the tires have radii of 0.18 m? Answer in units of rev.

Respuesta :

Answer:

184 revolutions

Explanation:

We will calculate the distance covered for by the car after the brakes are applied. We will apply the following equation of motion:

V^2=U^2 +2as where V is the final velocity, U is the initial velocity, a is the acceleration and s is the distance covered during that acceleration.

0=26.1^2 -2*1.64*s (-ve because it is decelerating).

S=207.7 or 208;

Circumference of the tire = 2[tex]\pi[/tex]r where r is the radius.

Circumference = 1.13

Distance / circumference = # of revolutions.

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