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A farmhand attaches a 25-kg bale of hay to one end of a rope passing over a
frictionless pulley connected to a beam in the hay barn. Another farmhand then
pulls down on the opposite end of the rope with a force of 277 N. Ignoring the
mass of the rope, what will be the magnitude and direction of the bale's
acceleration if the gravitational force acting on it is 245 N?

Respuesta :

MathPhys

Explanation:

Newton's second law:

∑F = ma

277 N − 245 N = (25 kg) a

a = 1.28 m/s²

Acceleration will be  a = 32/25 = 1.28 [tex]ms^{-2}[/tex]

What is newton's second law of motion ?

Newton's second law of motion  states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it and when mass is constant force is mass times acceleration

Let  F1 = 277 N

F2 = 245

mass = 25 kg

acceleration (a) = ?

according to Newton's second law of motion  

net force = F1 + F2 = ma

Net force on an object = 277 + (- 245) = 25 * a

                                       32 = 25 * a

                                        a = 32/25 = 1.28 [tex]ms^{-2}[/tex]

learn more about Newton's second law of motion:

https://brainly.com/question/13447525

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