Answer:
[tex]A=16(4-\pi)\approx 13.7[/tex]
Step-by-step explanation:
Subtractive Areas
If a greater surface area contains two or more non-overlapping surfaces, we can compute any of them by subtraction.
We have a figure where a circle is inscribed into a square of side length 8. The radius of the circle is half the side, i.e. r=4
The area of the square is
[tex]A_s=l^2=8^2=64[/tex]
The area of the circle is
[tex]A_c=\pi r^2=\pi 4^2=16\pi[/tex]
The shaded area is
[tex]A=A_s-A_c=64-16\pi[/tex]
[tex]A=16(4-\pi)\approx 13.7[/tex]
