Answer:
Explanation:
Given
mass of cart with bricks [tex]m=28.3\ kg[/tex]
inclination [tex]\theta =23.1^{\circ}[/tex]
distance moved [tex]s=28.7\ m[/tex]
coefficient of kinetic friction [tex]\mu _k=0.2[/tex]
it is given that cart is moving with constant velocity so net force on it is Zero
if T is the tension in rope
Net normal Reaction
[tex]N=mg-T\sin \theta [/tex]
Friction force [tex]f_r=\mu _k\cdot N[/tex]
[tex]f_r=\mu _k(mg-T\sin \theta )[/tex]
Horizontal force [tex]=T\cos \theta [/tex]
therefore
[tex]T\cos \theta =\mu _k(mg-T\sin \theta )[/tex]
[tex]T=\frac{\mu _kmg}{\cos \theta +\mu_k\sin \theta }[/tex]
[tex]T=\frac{55.468}{0.9982}[/tex]
[tex]T=55.56\ N[/tex]
work done [tex]W=T\cos \theta \cdot s[/tex]
[tex]W=55.56\cos (23.1)\cdot 28.7[/tex]
[tex]W=1466.93\ J[/tex]
