Answer:
The mass of water is [tex]1.7661\times10^{9}\ kg[/tex]
Explanation:
Given that,
Area of town = 29 km²
Time = 30 min
Height = 2.4 inch
Mass = 103 kg
We know that,
1 m = 39.37 inch
So, [tex]2.4\ inch =\dfrac{2.4}{39.37}[/tex]
[tex]2.4\ inch=0.0609\ m[/tex]
We need to calculate the volume
Using formula of volume
[tex]V=H\times A[/tex]
Put the value into the formula
[tex]V=0.0609\times29\times1000^2[/tex]
[tex]V=1766100\ m^3[/tex]
We need to calculate the mass of water
Using formula of density
[tex]\rho=\dfrac{m}{V}[/tex]
Put the value into the formula
[tex]1000=\dfrac{m}{1766100}[/tex]
[tex]m=1000\times1766100[/tex]
[tex]m=1.7661\times10^{9}\ kg[/tex]
Hence, The mass of water is [tex]1.7661\times10^{9}\ kg[/tex]
