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Two cars, a Porsche Boxster and a Toyota Scion XB, are traveling in the same direction, although the Boxster is 125.0 m behind the Scion. The speed of the Boxster is 26.4 m/s and the speed of the Scion is 15.6 m/s. How much time does it take for the Boxster to catch the Scion?

Respuesta :

Answer: t = 11.57s

The time taken for the Boxster to catch the Scion is 11.57s

Step-by-step explanation:

Given;

Speed of the boxster = 26.4m/s

Speed of the Scion = 15.6m/s

Assuming the starting point of 0 for the boxter, the starting point of the Scion would be 125.0m.

Given that;

Distance = speed × time

For the Boxster the distance travelled is;

d = 0 + 26.4t

For the scion the distance travelled is ;

d = 125 + 15.6t

Where t is the time.

Equating the two distance;

26.4t = 125 + 15.6t

26.4t - 15.6t = 125

t = 125/(26.4-15.6)

t = 11.57s

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