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A chemist prepares a solution of copper(II) fluoride (CuF2 by measuring out 0.0498g of copper(II) fluoride into a 100 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to significant digits.

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Answer:

4.90 × 10⁻³ M

Explanation:

Given data

  • Mass of copper(II) fluoride (solute): 0.0498 g
  • Volume of solution: 100 mL = 0.100 L

The molar mass of copper(II) fluoride is 101.54 g/mol. The moles corresponding to 0.0498 g are:

0.0498 g × (1 mol/101.54 g) = 4.90 × 10⁻⁴ mol

The molar concentration of copper(II) fluoride is:

4.90 × 10⁻⁴ mol/0.100 L = 4.90 × 10⁻³ M

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