Find the equation of the line that is parallel to 3x-4y=6 and passes through the point (-12,10)

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16-01-2020
Mathematics

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Find the equation of the line that is parallel to 3x-4y=6 and passes through the point (-12,10)

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keelanM keelanM · Answer 1 · 2020-01-16T20:21:53+01:00

Answer:

y = 3/4x + 19

Explanation:

First we need to write the equation in the form y=mx+c:

3x-4y=6
-4y=-3x+6
y=3/4x-3/2

Because the lines are parallel, we can deduce that the gradients (m) are equal. That means that the gradient of our new equation will also be 3/4.

We will now use the following equation:

y - y1 = m(x - x1)

We will substitute in the new line’s gradient as well as the coordinates we were given:

y - 10 = 3/4(x + 12)

Now we solve this equation into the form y=mx+c:

y - 10 = 3/4x + 9
y = 3/4x + 19

maggiejernas maggiejernas · Answer 2 · 2020-01-16T20:26:09+01:00

Answer:

Y = -4/3X +1

Step-by-step explanation:

To turn it into slope-intercept form, first divide by 4. Giving you 3/4X-Y= 1 1/2

Add 3/4X to each side for

Y= 3/4X + 1 1/2

Then, to make a line parallel to it, keep the first part (Y=3/4X) and now you have to find the intersects using the point (-12,10)

To find the intercept write the equation like this

(_)=(3/4)(_)+b (b is the intercept)

Replace the blanks with the points. The -12 goes where X goes.

The 10 goes where Y goes.

(10)=(3/4)(-12)+b

Now, multiply 3/4 and -12 for -36/4 or 9

Now subtract the nine (or X) from the 10 (or Y)

Now you have 1.

The intercept is 1.

Mark me as brainliest if this helps!