Answer:
The probability that 10 adults selected at random from the town all have health insurance is 0.01153.
Step-by-step explanation:
Consider the provided information.
One town, 64% of adults have health insurance.
Let p = 64% = 0.64
Therefore, q=1-0.64=0.36
We need to find the probability that 10 adults selected at random from the town all have health insurance
Use the formula: [tex]P(x)=^nC_r(p)^r(q)^{n-r}[/tex]
Here, the value of r is 10.
Substitute the respective values in the above formula.
[tex]P(x)=^{10}C_{10}(0.64)^{10}(0.36)^{10-10}[/tex]
[tex]P(x)=(0.64)^{10}(0.36)^{0}\\P(x)=(0.64)^{10}\\P(x)\approx0.01153[/tex]
Hence, the probability that 10 adults selected at random from the town all have health insurance is 0.01153.
