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What is the specific heat (J/g°C) of a metal object whose temperature increases by 3.0°C when 17.5 g of metal was heated with 38.5 J? a. 0.73 b. 0.15 c. 1.4 d. 4.18 e. none of the above

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Answer:

a. 0.73

Explanation:

Given data

  • Added heat (Q): 38.5 J
  • Change in the temperature (ΔT): 3.0°C
  • Mass of the metal (m): 17.5 g
  • Specific heat of the metal (c): ?

We can determine the specific heat of the metal using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 38.5 J / 17.5 g × 3.0°C

c = 0.73 J/g.°C

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