Answer:924.53 K
Explanation:
Given
gas is compressed to one-sixteen of the original volume
i.e. if [tex]V_1[/tex] is the initial volume then [tex]V_2=\frac{V_1}{16}[/tex]
Also Pressure is increased to 48.5 times of original value
i.e. [tex]P_2=48.5 P_1[/tex]
[tex]T_1=305\ K[/tex]
using [tex]PV=nRT[/tex]
[tex]P_1V_1=nRT_1-----1[/tex]
after the compression
[tex]P_2V_2=nRT_2[/tex]
[tex]48.5P_1\times \frac{V_1}{16}=nRT_2------2[/tex]
Divide 1 and 2 we get
[tex]\frac{16}{48.5}=\frac{T_1}{T_2}[/tex]
[tex]T_2=\frac{48.5}{16}\times T_1[/tex]
[tex]T_2=924.53\ K[/tex]
