Respuesta :
Answer:
a. The gram formula mass of CaSO4.2H2O equals 172 grams/mole
b. The percentage by mass of H2O in CaSO4.2H2O is 20.9%
c. The molecular formula for naphthalene is C10H8
d. The total number of moles in 80.0grams of C2H5Cl is 1.24 moles
e. 4.76moles of Na3PO4 contains 780.64 grams of Na3PO4
Explanation:
RMM = Relative Molecular Mass
a. To calculate the gram formula mass of CaSO4.2H2O, you would have to add the atomic mass of the individual elements that make up to compound. Here are the atomic masses of individual elements present in gypsum; Ca=40, S=32, O=16, H=1.
CaSO4.2H2O = 40+32+(16x4)+2((1x2)+16) = 172 grams/mole
b. % by mass of H2O in gypsum = (RMM of 2H2O/RMM of gypsum) x 100
RMM of 2H2O = 2((1x2)+16)=36 gram/mole
RMM of CaSO4.2H2O (gypsum) = 172 grams/mole
% by mass of H2O in gypsum = (36/172) x 100 = 20.9% of H2O
c. The empirical formula of a compound only shows the simplest ratio of atoms in a particular compound not the actual number of atoms. The actual number of atoms in a compound is shown in its molecular formula, which can be used to calculate the RMM of the compound. A specific number (n) multiplied by the number of atoms in an empirical formula gives the molecular formula. (C=12, H=1)
(Empirical formula)n = Molecular formula
(Total sum of atomic masses of elements in empirical formula)n = Total sum of atomic masses of elements in molecular formula
RMM of naphthalene = 128 grams/mole
((12x5)+(1x4))n = 64n
64n = 128
n = 128/64 = 2
Therefore, (C5H4)2 = C(5x2)H(4x2) = C10H8
d. Number of moles of C2H5Cl = mass of C2H5Cl/RMM of C2H5Cl
Say number of moles of C2H5Cl = y
Mass of C2H5Cl = 80.0 grams
RMM or gram-formula mass of C2H5Cl = 64.5 grams/mole
y = 80.0/64.5 = 1.24 moles
e. Number of moles of Na3PO4 = mass of Na3PO4/RMM of Na3PO4
Number of moles of Na3PO4 = 4.76 moles
gram-formula mass of Na3PO4 = 164 grams/mole
mass of Na3PO4 = x
4.76 = x/164
x = 4.76 x 164 = 780.64 grams
The number of moles is the ratio of mass to molar mass of a compound.
a) We know that the formula of gypsum is CaSO4.2H20. Hence, the percentage by mass of water in gypsum is obtained from;
2(18)/172 × 100/1
b) To obtain the molecular formula;
[5(12) + 4(1)]n = 128
n = 128/64
n = 2
The molecular formula is C10H8
c) The formula mass of C2H5Cl = 64.5 grams/mole
Number of moles = mass/ formula mass = 80.0 grams/64.5 grams/mole
= 1.24 moles
d) Formula mass of Na3PO4 = 164 grams/mole
Number of moles = mass/ formula mass
mass = Number of moles * formula mass = 4.76 moles * 164 grams/mole
= 781 g
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