The potential energy on the moon would be 1/6 of the potential energy on Earth
Explanation:
The potential energy of an object is the energy possessed by the object due to its position in a gravitational field, and it is given by
[tex]PE=mgh[/tex]
where
m is the mass of the object
g is the strength of the gravitational field
h is the height of the object above the ground
In this problem, the potential energy of the object on the Earth is
[tex]PE=mgh[/tex]
On the Moon, the gravity is
[tex]g'=\frac{1}{6}g[/tex]
Therefore, if the same object (same mass) is placed at the same height [tex]h[/tex] on the Moon, its potential energy would be
[tex]PE' = m(\frac{1}{6}g)h = \frac{1}{6}(mgh) = \frac{1}{6}PE'[/tex]
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