Answer:
The sample size should be approximately 167.
Step-by-step explanation:
We are given the following in the question
Sample size, n = 10
Confidence level = 99%
Significance level = 0.01
Standard deviation, σ = 50
Error = 10
Formula:
[tex]\text{Marginal error} = z_{critical}\frac{\sigma}{\sqrt{n}}[/tex]
Ptting values, we get,
[tex]z_{critical}\text{ at}~\alpha_{0.05} = \pm 2.58[/tex]
[tex]10 = 2.58\times \dfrac{50}{\sqrt{n}}\\\\n = \bigg(\dfrac{2.58\times 50}{10}\bigg)^2\\\\n = 166.41\approx 167[/tex]
The sample size should be approximately 167.