The force of box C on box B is 32.34 N
Explanation:
To solve this problem, we have to consider the forces acting on box B.
There are three forces acting on box B:
- The weight of box B, [tex]W_B[/tex], downward
- The push exerted from box A on box B, which is equal to the weight of box A, [tex]W_A[/tex], also downward
- The normal force exerted by box C on box B, [tex]N[/tex], upward (this is the force we are looking for)
Since the box is in equilibrium, we can write the equation:
[tex]W_A + W_B - N = 0\\m_A g + m_B g - N = 0[/tex]
where
[tex]m_A = 1.5 kg[/tex] is the mass of box A
[tex]m_B = 1.8 kg[/tex] is the mass of box B
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Solving for N, we find
[tex]N=(m_A + m_B)g=(1.5+1.8)(9.8)=32.34 N[/tex]
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