The foot length of Sandy is 10.5 inches
Solution:
Assume nose and foot length are proportional
Therefore,
[tex]\text{ nose length } \propto \text{ foot length }[/tex]
Let "n" be the nose length and "f" be the foot length
Then,
[tex]n \propto f[/tex]
n = kf ------ eqn 1
Where "k" is the constant of proportionality
Cindy's nose is 1.9 inches long and her foot is 9.5 inches long
n = 1.9 inches'
f = 9.5 inches
Substitute these in eqn 1
[tex]1.9 = k(9.5)\\\\k = \frac{1.9}{9.5} = 0.2[/tex]
Thus k = 0.2
Sandy's nose is 2.1 inches long, we have to find the foot length
n = 2.1
k = 0.2
f = ?
Substitute these in eqn 1
[tex]2.1 = 0.2 \times f\\\\f = \frac{2.1}{0.2} = 10.5[/tex]
Thus foot length of Sandy is 10.5 inches
